알고리즘/SQL
[SQL] 조건에 맞는 사원 정보 조회하기
moongi
2025. 5. 16. 11:05
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WTIH SUM_SCORE AS (
SELECT EMP_NO
,SUM(SCORE) AS SCORE
FROM HR_GRADE
GROUP BY EMP_NO
), RANKING AS (
SELECT EMP_NO
, SCORE
, DENSE_RANK() OVER (ORDER BY SCORE DESC) AS DR
FROM SUM_SCORE
)
SELECT RK.SCORE
, RK.EMP_NO
, HE.EMP_NAME
, HE.POSITION
, HE.EMAIL
FROM HR_EMPLOYEES HE
INNER JOIN RANKING RK ON HE.EMP_NO = RK.EMP_NO
WHERE RK.DR = 1;
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